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Find the right answer to the question ✅ *With what force do two charges 0.66*10^-7 Cl and 1.1*10^-5 Cl interact at a distance of 3.3 cm in the air?* in the category Physics, And if there is no answer or no one gave the right answer, then use the search and try to find the answer among similar questions.

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The force between two charges is given by Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Therefore, the force between 0.66*10^-7 Cl and 1.1*10^-5 Cl at a distance of 3.3 cm in the air can be calculated as follows:

F = (k * q1 * q2) / d^2

Where,

k = 8.99 * 10^9 Nm^2/C^2

q1 = 0.66 * 10^-7 C

q2 = 1.1 * 10^-5 C

d = 3.3 cm

F = (8.99 * 10^9 Nm^2/C^2 * 0.66 * 10^-7 C * 1.1 * 10^-5 C) / (3.3 cm)^2

F = 0.193 N

Therefore, the force between the two charges 0.66*10^-7 Cl and 1.1*10^-5 Cl at a distance of 3.3 cm in the air is 0.193 N.